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/* Allocate memory region filled with spaces.
Copyright (C) 1991 Free Software Foundation, Inc.
This file is part of the libiberty library.
Libiberty is free software; you can redistribute it and/or
modify it under the terms of the GNU Library General Public
License as published by the Free Software Foundation; either
version 2 of the License, or (at your option) any later version.
Libiberty is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
Library General Public License for more details.
You should have received a copy of the GNU Library General Public
License along with libiberty; see the file COPYING.LIB. If
not, write to the Free Software Foundation, Inc., 675 Mass Ave,
Cambridge, MA 02139, USA. */
/*
NAME
spaces -- return a pointer to a buffer full of spaces
SYNOPSIS
char *spaces (int count)
DESCRIPTION
Returns a pointer to a memory region filled with the specified
number of spaces and null terminated. The returned pointer is
valid until at least the next call.
BUGS
*/
char *
spaces (count)
int count;
{
register char *t;
static char *buf;
static int maxsize;
extern char *malloc ();
extern void free ();
if (count > maxsize)
{
if (buf)
{
free (buf);
}
buf = malloc (count + 1);
for (t = buf + count ; t != buf ; )
{
*--t = ' ';
}
maxsize = count;
buf[count] = '\0';
}
return (buf + maxsize - count);
}
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