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"""
Test that lldb persistent types works correctly.
"""
from __future__ import print_function
import os, time
import lldb
from lldbsuite.test.lldbtest import *
class PersistenttypesTestCase(TestBase):
mydir = TestBase.compute_mydir(__file__)
@expectedFailureWindows("llvm.org/pr21765")
def test_persistent_types(self):
"""Test that lldb persistent types works correctly."""
self.build()
self.runCmd("file a.out", CURRENT_EXECUTABLE_SET)
self.runCmd("breakpoint set --name main")
self.runCmd("run", RUN_SUCCEEDED)
self.runCmd("expression struct $foo { int a; int b; };")
self.expect("expression struct $foo $my_foo; $my_foo.a = 2; $my_foo.b = 3;",
startstr = "(int) $0 = 3")
self.expect("expression $my_foo",
substrs = ['a = 2', 'b = 3'])
self.runCmd("expression typedef int $bar")
self.expect("expression $bar i = 5; i",
startstr = "($bar) $1 = 5")
self.runCmd("expression struct $foobar { char a; char b; char c; char d; };")
self.runCmd("next")
self.expect("memory read foo -t $foobar",
substrs = ['($foobar) 0x', ' = ', "a = 'H'","b = 'e'","c = 'l'","d = 'l'"]) # persistent types are OK to use for memory read
self.expect("memory read foo -t foobar",
substrs = ['($foobar) 0x', ' = ', "a = 'H'","b = 'e'","c = 'l'","d = 'l'"],matching=False,error=True) # the type name is $foobar, make sure we settle for nothing less
self.expect("expression struct { int a; int b; } x = { 2, 3 }; x",
substrs = ['a = 2', 'b = 3'])
self.expect("expression struct { int x; int y; int z; } object; object.y = 1; object.z = 3; object.x = 2; object",
substrs = ['x = 2', 'y = 1', 'z = 3'])
self.expect("expression struct A { int x; int y; }; struct { struct A a; int z; } object; object.a.y = 1; object.z = 3; object.a.x = 2; object",
substrs = ['x = 2', 'y = 1', 'z = 3'])
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